2(3u-1)+2u=5-(2u-3)

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Solution for 2(3u-1)+2u=5-(2u-3) equation:



2(3u-1)+2u=5-(2u-3)
We move all terms to the left:
2(3u-1)+2u-(5-(2u-3))=0
We add all the numbers together, and all the variables
2u+2(3u-1)-(5-(2u-3))=0
We multiply parentheses
2u+6u-(5-(2u-3))-2=0
We calculate terms in parentheses: -(5-(2u-3)), so:
5-(2u-3)
determiningTheFunctionDomain -(2u-3)+5
We get rid of parentheses
-2u+3+5
We add all the numbers together, and all the variables
-2u+8
Back to the equation:
-(-2u+8)
We add all the numbers together, and all the variables
8u-(-2u+8)-2=0
We get rid of parentheses
8u+2u-8-2=0
We add all the numbers together, and all the variables
10u-10=0
We move all terms containing u to the left, all other terms to the right
10u=10
u=10/10
u=1

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