2(3u-1)+8u+5=6(u-5)-3u

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Solution for 2(3u-1)+8u+5=6(u-5)-3u equation: 



2(3u-1)+8u+5=6(u-5)-3u

We move all terms to the left:

2(3u-1)+8u+5-(6(u-5)-3u)=0

We add all the numbers together, and all the variables

8u+2(3u-1)-(6(u-5)-3u)+5=0

We multiply parentheses

8u+6u-(6(u-5)-3u)-2+5=0



We calculate terms in parentheses: -(6(u-5)-3u), so:

6(u-5)-3u

We add all the numbers together, and all the variables

-3u+6(u-5)

We multiply parentheses

-3u+6u-30

We add all the numbers together, and all the variables

3u-30

Back to the equation:

-(3u-30)



We add all the numbers together, and all the variables

14u-(3u-30)+3=0

We get rid of parentheses

14u-3u+30+3=0

We add all the numbers together, and all the variables

11u+33=0

We move all terms containing u to the left, all other terms to the right

11u=-33

u=-33/11

u=-3

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