2(3v-2)+6v+6=4(v-4)+2v

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Solution for 2(3v-2)+6v+6=4(v-4)+2v equation: 



2(3v-2)+6v+6=4(v-4)+2v

We move all terms to the left:

2(3v-2)+6v+6-(4(v-4)+2v)=0

We add all the numbers together, and all the variables

6v+2(3v-2)-(4(v-4)+2v)+6=0

We multiply parentheses

6v+6v-(4(v-4)+2v)-4+6=0



We calculate terms in parentheses: -(4(v-4)+2v), so:

4(v-4)+2v

We add all the numbers together, and all the variables

2v+4(v-4)

We multiply parentheses

2v+4v-16

We add all the numbers together, and all the variables

6v-16

Back to the equation:

-(6v-16)



We add all the numbers together, and all the variables

12v-(6v-16)+2=0

We get rid of parentheses

12v-6v+16+2=0

We add all the numbers together, and all the variables

6v+18=0

We move all terms containing v to the left, all other terms to the right

6v=-18

v=-18/6

v=-3

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