2(3v-5)=(2v-11)-4

Solution for 2(3v-5)=(2v-11)-4 equation:

2(3v-5)=(2v-11)-4

We move all terms to the left:

2(3v-5)-((2v-11)-4)=0

We multiply parentheses

6v-((2v-11)-4)-10=0


We calculate terms in parentheses: -((2v-11)-4), so:

(2v-11)-4

We get rid of parentheses

2v-11-4

We add all the numbers together, and all the variables

2v-15

Back to the equation:

-(2v-15)


We get rid of parentheses

6v-2v+15-10=0

We add all the numbers together, and all the variables

4v+5=0

We move all terms containing v to the left, all other terms to the right

4v=-5

v=-5/4

v=-1+1/4