2(3v-5)=2(1v-11)-4

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Solution for 2(3v-5)=2(1v-11)-4 equation: 



2(3v-5)=2(1v-11)-4

We move all terms to the left:

2(3v-5)-(2(1v-11)-4)=0

We add all the numbers together, and all the variables

2(3v-5)-(2(v-11)-4)=0

We multiply parentheses

6v-(2(v-11)-4)-10=0



We calculate terms in parentheses: -(2(v-11)-4), so:

2(v-11)-4

We multiply parentheses

2v-22-4

We add all the numbers together, and all the variables

2v-26

Back to the equation:

-(2v-26)



We get rid of parentheses

6v-2v+26-10=0

We add all the numbers together, and all the variables

4v+16=0

We move all terms containing v to the left, all other terms to the right

4v=-16

v=-16/4

v=-4

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