2(3v-5)=2(v-11)

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Solution for 2(3v-5)=2(v-11) equation: 



2(3v-5)=2(v-11)

We move all terms to the left:

2(3v-5)-(2(v-11))=0

We multiply parentheses

6v-(2(v-11))-10=0



We calculate terms in parentheses: -(2(v-11)), so:

2(v-11)

We multiply parentheses

2v-22

Back to the equation:

-(2v-22)



We get rid of parentheses

6v-2v+22-10=0

We add all the numbers together, and all the variables

4v+12=0

We move all terms containing v to the left, all other terms to the right

4v=-12

v=-12/4

v=-3

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