2(3v-5)=3(v-11)-4

Solution for 2(3v-5)=3(v-11)-4 equation:

2(3v-5)=3(v-11)-4

We move all terms to the left:

2(3v-5)-(3(v-11)-4)=0

We multiply parentheses

6v-(3(v-11)-4)-10=0


We calculate terms in parentheses: -(3(v-11)-4), so:

3(v-11)-4

We multiply parentheses

3v-33-4

We add all the numbers together, and all the variables

3v-37

Back to the equation:

-(3v-37)


We get rid of parentheses

6v-3v+37-10=0

We add all the numbers together, and all the variables

3v+27=0

We move all terms containing v to the left, all other terms to the right

3v=-27

v=-27/3

v=-9