2(3v-5v)=2(v-11)-4

Solution for 2(3v-5v)=2(v-11)-4 equation:

2(3v-5v)=2(v-11)-4

We move all terms to the left:

2(3v-5v)-(2(v-11)-4)=0

We add all the numbers together, and all the variables

2(-2v)-(2(v-11)-4)=0

We multiply parentheses

-4v-(2(v-11)-4)=0


We calculate terms in parentheses: -(2(v-11)-4), so:

2(v-11)-4

We multiply parentheses

2v-22-4

We add all the numbers together, and all the variables

2v-26

Back to the equation:

-(2v-26)


We get rid of parentheses

-4v-2v+26=0

We add all the numbers together, and all the variables

-6v+26=0

We move all terms containing v to the left, all other terms to the right

-6v=-26

v=-26/-6

v=4+1/3