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2(3x)-4=4/6x
We move all terms to the left:
2(3x)-4-(4/6x)=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
23x-(+4/6x)-4=0
We get rid of parentheses
23x-4/6x-4=0
We multiply all the terms by the denominator
23x*6x-4*6x-4=0
Wy multiply elements
138x^2-24x-4=0
a = 138; b = -24; c = -4;
Δ = b2-4ac
Δ = -242-4·138·(-4)
Δ = 2784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2784}=\sqrt{16*174}=\sqrt{16}*\sqrt{174}=4\sqrt{174}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{174}}{2*138}=\frac{24-4\sqrt{174}}{276} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{174}}{2*138}=\frac{24+4\sqrt{174}}{276} $
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