2(3x+)+6(x-8)=32

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Solution for 2(3x+)+6(x-8)=32 equation: 



2(3x+)+6(x-8)=32

We move all terms to the left:

2(3x+)+6(x-8)-(32)=0

We add all the numbers together, and all the variables

2(+3x)+6(x-8)-32=0

We multiply parentheses

6x+6x-48-32=0

We add all the numbers together, and all the variables

12x-80=0

We move all terms containing x to the left, all other terms to the right

12x=80

x=80/12

x=6+2/3

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