2(3x+0,5)=5(x-1,2)

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Solution for 2(3x+0,5)=5(x-1,2) equation: 



2(3x+0.5)=5(x-1.2)

We move all terms to the left:

2(3x+0.5)-(5(x-1.2))=0

We multiply parentheses

6x-(5(x-1.2))+1=0



We calculate terms in parentheses: -(5(x-1.2)), so:

5(x-1.2)

We multiply parentheses

5x-6

Back to the equation:

-(5x-6)



We get rid of parentheses

6x-5x+6+1=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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