2(3x+1)+1=3-(2x-4)

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Solution for 2(3x+1)+1=3-(2x-4) equation: 



2(3x+1)+1=3-(2x-4)

We move all terms to the left:

2(3x+1)+1-(3-(2x-4))=0

We multiply parentheses

6x-(3-(2x-4))+2+1=0



We calculate terms in parentheses: -(3-(2x-4)), so:

3-(2x-4)

determiningTheFunctionDomain
-(2x-4)+3

We get rid of parentheses

-2x+4+3

We add all the numbers together, and all the variables

-2x+7

Back to the equation:

-(-2x+7)



We add all the numbers together, and all the variables

6x-(-2x+7)+3=0

We get rid of parentheses

6x+2x-7+3=0

We add all the numbers together, and all the variables

8x-4=0

We move all terms containing x to the left, all other terms to the right

8x=4

x=4/8

x=1/2

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