2(3x+1)+4(2x-2)=2(7x+-3)

Solution for 2(3x+1)+4(2x-2)=2(7x+-3) equation:

Simplifying
2(3x + 1) + 4(2x + -2) = 2(7x + -3)

Reorder the terms:
2(1 + 3x) + 4(2x + -2) = 2(7x + -3)
(1 * 2 + 3x * 2) + 4(2x + -2) = 2(7x + -3)
(2 + 6x) + 4(2x + -2) = 2(7x + -3)

Reorder the terms:
2 + 6x + 4(-2 + 2x) = 2(7x + -3)
2 + 6x + (-2 * 4 + 2x * 4) = 2(7x + -3)
2 + 6x + (-8 + 8x) = 2(7x + -3)

Reorder the terms:
2 + -8 + 6x + 8x = 2(7x + -3)

Combine like terms: 2 + -8 = -6
-6 + 6x + 8x = 2(7x + -3)

Combine like terms: 6x + 8x = 14x
-6 + 14x = 2(7x + -3)

Reorder the terms:
-6 + 14x = 2(-3 + 7x)
-6 + 14x = (-3 * 2 + 7x * 2)
-6 + 14x = (-6 + 14x)

Add '6' to each side of the equation.
-6 + 6 + 14x = -6 + 6 + 14x

Combine like terms: -6 + 6 = 0
0 + 14x = -6 + 6 + 14x
14x = -6 + 6 + 14x

Combine like terms: -6 + 6 = 0
14x = 0 + 14x
14x = 14x

Add '-14x' to each side of the equation.
14x + -14x = 14x + -14x

Combine like terms: 14x + -14x = 0
0 = 14x + -14x

Combine like terms: 14x + -14x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.