2(3x+1)+5(3-2x)=-2(x+1)+7(3-x)

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Solution for 2(3x+1)+5(3-2x)=-2(x+1)+7(3-x) equation: 



2(3x+1)+5(3-2x)=-2(x+1)+7(3-x)

We move all terms to the left:

2(3x+1)+5(3-2x)-(-2(x+1)+7(3-x))=0

We add all the numbers together, and all the variables

2(3x+1)+5(-2x+3)-(-2(x+1)+7(-1x+3))=0

We multiply parentheses

6x-10x-(-2(x+1)+7(-1x+3))+2+15=0



We calculate terms in parentheses: -(-2(x+1)+7(-1x+3)), so:

-2(x+1)+7(-1x+3)

We multiply parentheses

-2x-7x-2+21

We add all the numbers together, and all the variables

-9x+19

Back to the equation:

-(-9x+19)



We add all the numbers together, and all the variables

-4x-(-9x+19)+17=0

We get rid of parentheses

-4x+9x-19+17=0

We add all the numbers together, and all the variables

5x-2=0

We move all terms containing x to the left, all other terms to the right

5x=2

x=2/5

x=2/5

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