2(3x+1)+5x=10(x-3)

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Solution for 2(3x+1)+5x=10(x-3) equation: 



2(3x+1)+5x=10(x-3)

We move all terms to the left:

2(3x+1)+5x-(10(x-3))=0

We add all the numbers together, and all the variables

5x+2(3x+1)-(10(x-3))=0

We multiply parentheses

5x+6x-(10(x-3))+2=0



We calculate terms in parentheses: -(10(x-3)), so:

10(x-3)

We multiply parentheses

10x-30

Back to the equation:

-(10x-30)



We add all the numbers together, and all the variables

11x-(10x-30)+2=0

We get rid of parentheses

11x-10x+30+2=0

We add all the numbers together, and all the variables

x+32=0

We move all terms containing x to the left, all other terms to the right

x=-32

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