2(3x+1)+6=4(x+20)

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Solution for 2(3x+1)+6=4(x+20) equation:


Simplifying
2(3x + 1) + 6 = 4(x + 20)

Reorder the terms:
2(1 + 3x) + 6 = 4(x + 20)
(1 * 2 + 3x * 2) + 6 = 4(x + 20)
(2 + 6x) + 6 = 4(x + 20)

Reorder the terms:
2 + 6 + 6x = 4(x + 20)

Combine like terms: 2 + 6 = 8
8 + 6x = 4(x + 20)

Reorder the terms:
8 + 6x = 4(20 + x)
8 + 6x = (20 * 4 + x * 4)
8 + 6x = (80 + 4x)

Solving
8 + 6x = 80 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
8 + 6x + -4x = 80 + 4x + -4x

Combine like terms: 6x + -4x = 2x
8 + 2x = 80 + 4x + -4x

Combine like terms: 4x + -4x = 0
8 + 2x = 80 + 0
8 + 2x = 80

Add '-8' to each side of the equation.
8 + -8 + 2x = 80 + -8

Combine like terms: 8 + -8 = 0
0 + 2x = 80 + -8
2x = 80 + -8

Combine like terms: 80 + -8 = 72
2x = 72

Divide each side by '2'.
x = 36

Simplifying
x = 36

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