2(3x+1)+7=8x-(3-2x)

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Solution for 2(3x+1)+7=8x-(3-2x) equation: 



2(3x+1)+7=8x-(3-2x)

We move all terms to the left:

2(3x+1)+7-(8x-(3-2x))=0

We add all the numbers together, and all the variables

2(3x+1)-(8x-(-2x+3))+7=0

We multiply parentheses

6x-(8x-(-2x+3))+2+7=0



We calculate terms in parentheses: -(8x-(-2x+3)), so:

8x-(-2x+3)

We get rid of parentheses

8x+2x-3

We add all the numbers together, and all the variables

10x-3

Back to the equation:

-(10x-3)



We add all the numbers together, and all the variables

6x-(10x-3)+9=0

We get rid of parentheses

6x-10x+3+9=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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