2(3x+1)+x-2=10x-32

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Solution for 2(3x+1)+x-2=10x-32 equation: 



2(3x+1)+x-2=10x-32

We move all terms to the left:

2(3x+1)+x-2-(10x-32)=0

We add all the numbers together, and all the variables

x+2(3x+1)-(10x-32)-2=0

We multiply parentheses

x+6x-(10x-32)+2-2=0

We get rid of parentheses

x+6x-10x+32+2-2=0

We add all the numbers together, and all the variables

-3x+32=0

We move all terms containing x to the left, all other terms to the right

-3x=-32

x=-32/-3

x=10+2/3

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