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2(3x+1)-2x=4(x+2)
We move all terms to the left:
2(3x+1)-2x-(4(x+2))=0
We add all the numbers together, and all the variables
-2x+2(3x+1)-(4(x+2))=0
We multiply parentheses
-2x+6x-(4(x+2))+2=0
We calculate terms in parentheses: -(4(x+2)), so:We add all the numbers together, and all the variables
4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
4x-(4x+8)+2=0
We get rid of parentheses
4x-4x-8+2=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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