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2(3x+1)-3(1-2x)=7(x+2)
We move all terms to the left:
2(3x+1)-3(1-2x)-(7(x+2))=0
We add all the numbers together, and all the variables
2(3x+1)-3(-2x+1)-(7(x+2))=0
We multiply parentheses
6x+6x-(7(x+2))+2-3=0
We calculate terms in parentheses: -(7(x+2)), so:We add all the numbers together, and all the variables
7(x+2)
We multiply parentheses
7x+14
Back to the equation:
-(7x+14)
12x-(7x+14)-1=0
We get rid of parentheses
12x-7x-14-1=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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