2(3x+1)-5(x+2)=0

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Solution for 2(3x+1)-5(x+2)=0 equation:


Simplifying
2(3x + 1) + -5(x + 2) = 0

Reorder the terms:
2(1 + 3x) + -5(x + 2) = 0
(1 * 2 + 3x * 2) + -5(x + 2) = 0
(2 + 6x) + -5(x + 2) = 0

Reorder the terms:
2 + 6x + -5(2 + x) = 0
2 + 6x + (2 * -5 + x * -5) = 0
2 + 6x + (-10 + -5x) = 0

Reorder the terms:
2 + -10 + 6x + -5x = 0

Combine like terms: 2 + -10 = -8
-8 + 6x + -5x = 0

Combine like terms: 6x + -5x = 1x
-8 + 1x = 0

Solving
-8 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1x = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1x = 0 + 8
1x = 0 + 8

Combine like terms: 0 + 8 = 8
1x = 8

Divide each side by '1'.
x = 8

Simplifying
x = 8

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