2(3x+1)-5=x-(x+2)

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Solution for 2(3x+1)-5=x-(x+2) equation: 



2(3x+1)-5=x-(x+2)

We move all terms to the left:

2(3x+1)-5-(x-(x+2))=0

We multiply parentheses

6x-(x-(x+2))+2-5=0



We calculate terms in parentheses: -(x-(x+2)), so:

x-(x+2)

We get rid of parentheses

x-x-2

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

6x-1=0

We move all terms containing x to the left, all other terms to the right

6x=1

x=1/6

x=1/6

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