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2(3x+1)=-2(5x-5)+5x
We move all terms to the left:
2(3x+1)-(-2(5x-5)+5x)=0
We multiply parentheses
6x-(-2(5x-5)+5x)+2=0
We calculate terms in parentheses: -(-2(5x-5)+5x), so:We get rid of parentheses
-2(5x-5)+5x
We add all the numbers together, and all the variables
5x-2(5x-5)
We multiply parentheses
5x-10x+10
We add all the numbers together, and all the variables
-5x+10
Back to the equation:
-(-5x+10)
6x+5x-10+2=0
We add all the numbers together, and all the variables
11x-8=0
We move all terms containing x to the left, all other terms to the right
11x=8
x=8/11
x=8/11
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