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2(3x+1)=-3(5x-4)
We move all terms to the left:
2(3x+1)-(-3(5x-4))=0
We multiply parentheses
6x-(-3(5x-4))+2=0
We calculate terms in parentheses: -(-3(5x-4)), so:We get rid of parentheses
-3(5x-4)
We multiply parentheses
-15x+12
Back to the equation:
-(-15x+12)
6x+15x-12+2=0
We add all the numbers together, and all the variables
21x-10=0
We move all terms containing x to the left, all other terms to the right
21x=10
x=10/21
x=10/21
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