2(3x+1)=12+2(4x+3)

Solution for 2(3x+1)=12+2(4x+3) equation:

2(3x+1)=12+2(4x+3)

We move all terms to the left:

2(3x+1)-(12+2(4x+3))=0

We multiply parentheses

6x-(12+2(4x+3))+2=0


We calculate terms in parentheses: -(12+2(4x+3)), so:

12+2(4x+3)

determiningTheFunctionDomain
2(4x+3)+12

We multiply parentheses

8x+6+12

We add all the numbers together, and all the variables

8x+18

Back to the equation:

-(8x+18)


We get rid of parentheses

6x-8x-18+2=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8