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2(3x+1)=2(2x-5)-4
We move all terms to the left:
2(3x+1)-(2(2x-5)-4)=0
We multiply parentheses
6x-(2(2x-5)-4)+2=0
We calculate terms in parentheses: -(2(2x-5)-4), so:We get rid of parentheses
2(2x-5)-4
We multiply parentheses
4x-10-4
We add all the numbers together, and all the variables
4x-14
Back to the equation:
-(4x-14)
6x-4x+14+2=0
We add all the numbers together, and all the variables
2x+16=0
We move all terms containing x to the left, all other terms to the right
2x=-16
x=-16/2
x=-8
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