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2(3x+1)=3(x+6)-1
We move all terms to the left:
2(3x+1)-(3(x+6)-1)=0
We multiply parentheses
6x-(3(x+6)-1)+2=0
We calculate terms in parentheses: -(3(x+6)-1), so:We get rid of parentheses
3(x+6)-1
We multiply parentheses
3x+18-1
We add all the numbers together, and all the variables
3x+17
Back to the equation:
-(3x+17)
6x-3x-17+2=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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