2(3x+1)=3(x-2)+29

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Solution for 2(3x+1)=3(x-2)+29 equation: 



2(3x+1)=3(x-2)+29

We move all terms to the left:

2(3x+1)-(3(x-2)+29)=0

We multiply parentheses

6x-(3(x-2)+29)+2=0



We calculate terms in parentheses: -(3(x-2)+29), so:

3(x-2)+29

We multiply parentheses

3x-6+29

We add all the numbers together, and all the variables

3x+23

Back to the equation:

-(3x+23)



We get rid of parentheses

6x-3x-23+2=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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