2(3x+1)=3(x-2+29)

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Solution for 2(3x+1)=3(x-2+29) equation: 



2(3x+1)=3(x-2+29)

We move all terms to the left:

2(3x+1)-(3(x-2+29))=0

We add all the numbers together, and all the variables

2(3x+1)-(3(x+27))=0

We multiply parentheses

6x-(3(x+27))+2=0



We calculate terms in parentheses: -(3(x+27)), so:

3(x+27)

We multiply parentheses

3x+81

Back to the equation:

-(3x+81)



We get rid of parentheses

6x-3x-81+2=0

We add all the numbers together, and all the variables

3x-79=0

We move all terms containing x to the left, all other terms to the right

3x=79

x=79/3

x=26+1/3

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