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2(3x+1)=5(2x-2)
We move all terms to the left:
2(3x+1)-(5(2x-2))=0
We multiply parentheses
6x-(5(2x-2))+2=0
We calculate terms in parentheses: -(5(2x-2)), so:We get rid of parentheses
5(2x-2)
We multiply parentheses
10x-10
Back to the equation:
-(10x-10)
6x-10x+10+2=0
We add all the numbers together, and all the variables
-4x+12=0
We move all terms containing x to the left, all other terms to the right
-4x=-12
x=-12/-4
x=+3
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