2(3x+1)=58

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Solution for 2(3x+1)=58 equation: 



2(3x+1)=58

We move all terms to the left:

2(3x+1)-(58)=0

We multiply parentheses

6x+2-58=0

We add all the numbers together, and all the variables

6x-56=0

We move all terms containing x to the left, all other terms to the right

6x=56

x=56/6

x=9+1/3

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