2(3x+1)=6+4x2

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Solution for 2(3x+1)=6+4x2 equation: 



2(3x+1)=6+4x^2

We move all terms to the left:

2(3x+1)-(6+4x^2)=0

We multiply parentheses

-(6+4x^2)+6x+2=0

We get rid of parentheses

-4x^2+6x-6+2=0

We add all the numbers together, and all the variables

-4x^2+6x-4=0

a = -4; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·(-4)·(-4)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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