2(3x+1)=x2+18

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Solution for 2(3x+1)=x2+18 equation: 



2(3x+1)=x2+18

We move all terms to the left:

2(3x+1)-(x2+18)=0

We add all the numbers together, and all the variables

-(+x^2+18)+2(3x+1)=0

We multiply parentheses

-(+x^2+18)+6x+2=0

We get rid of parentheses

-x^2+6x-18+2=0

We add all the numbers together, and all the variables

-1x^2+6x-16=0

a = -1; b = 6; c = -16;
Δ = b2-4ac
Δ = 62-4·(-1)·(-16)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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