2(3x+2)+2(4x-2)=140

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Solution for 2(3x+2)+2(4x-2)=140 equation: 



2(3x+2)+2(4x-2)=140

We move all terms to the left:

2(3x+2)+2(4x-2)-(140)=0

We multiply parentheses

6x+8x+4-4-140=0

We add all the numbers together, and all the variables

14x-140=0

We move all terms containing x to the left, all other terms to the right

14x=140

x=140/14

x=10

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