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2(3x+2)+3(2x+3)+3=12x+16
We move all terms to the left:
2(3x+2)+3(2x+3)+3-(12x+16)=0
We multiply parentheses
6x+6x-(12x+16)+4+9+3=0
We get rid of parentheses
6x+6x-12x-16+4+9+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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