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2(3x+2)-5=4(1-x)
We move all terms to the left:
2(3x+2)-5-(4(1-x))=0
We add all the numbers together, and all the variables
2(3x+2)-(4(-1x+1))-5=0
We multiply parentheses
6x-(4(-1x+1))+4-5=0
We calculate terms in parentheses: -(4(-1x+1)), so:We add all the numbers together, and all the variables
4(-1x+1)
We multiply parentheses
-4x+4
Back to the equation:
-(-4x+4)
6x-(-4x+4)-1=0
We get rid of parentheses
6x+4x-4-1=0
We add all the numbers together, and all the variables
10x-5=0
We move all terms containing x to the left, all other terms to the right
10x=5
x=5/10
x=1/2
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