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2(3x+2)=-5(2x-5)+3x
We move all terms to the left:
2(3x+2)-(-5(2x-5)+3x)=0
We multiply parentheses
6x-(-5(2x-5)+3x)+4=0
We calculate terms in parentheses: -(-5(2x-5)+3x), so:We get rid of parentheses
-5(2x-5)+3x
We add all the numbers together, and all the variables
3x-5(2x-5)
We multiply parentheses
3x-10x+25
We add all the numbers together, and all the variables
-7x+25
Back to the equation:
-(-7x+25)
6x+7x-25+4=0
We add all the numbers together, and all the variables
13x-21=0
We move all terms containing x to the left, all other terms to the right
13x=21
x=21/13
x=1+8/13
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