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2(3x+2)=2(-3x+2)
We move all terms to the left:
2(3x+2)-(2(-3x+2))=0
We multiply parentheses
6x-(2(-3x+2))+4=0
We calculate terms in parentheses: -(2(-3x+2)), so:We get rid of parentheses
2(-3x+2)
We multiply parentheses
-6x+4
Back to the equation:
-(-6x+4)
6x+6x-4+4=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0
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