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2(3x+2)=23(x+5)
We move all terms to the left:
2(3x+2)-(23(x+5))=0
We multiply parentheses
6x-(23(x+5))+4=0
We calculate terms in parentheses: -(23(x+5)), so:We get rid of parentheses
23(x+5)
We multiply parentheses
23x+115
Back to the equation:
-(23x+115)
6x-23x-115+4=0
We add all the numbers together, and all the variables
-17x-111=0
We move all terms containing x to the left, all other terms to the right
-17x=111
x=111/-17
x=-6+9/17
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