2(3x+2)=23(x+5)

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Solution for 2(3x+2)=23(x+5) equation: 



2(3x+2)=23(x+5)

We move all terms to the left:

2(3x+2)-(23(x+5))=0

We multiply parentheses

6x-(23(x+5))+4=0



We calculate terms in parentheses: -(23(x+5)), so:

23(x+5)

We multiply parentheses

23x+115

Back to the equation:

-(23x+115)



We get rid of parentheses

6x-23x-115+4=0

We add all the numbers together, and all the variables

-17x-111=0

We move all terms containing x to the left, all other terms to the right

-17x=111

x=111/-17

x=-6+9/17

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