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2(3x+2)=5(x-1)+6
We move all terms to the left:
2(3x+2)-(5(x-1)+6)=0
We multiply parentheses
6x-(5(x-1)+6)+4=0
We calculate terms in parentheses: -(5(x-1)+6), so:We get rid of parentheses
5(x-1)+6
We multiply parentheses
5x-5+6
We add all the numbers together, and all the variables
5x+1
Back to the equation:
-(5x+1)
6x-5x-1+4=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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