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2(3x+3)-3(x-1)=15
We move all terms to the left:
2(3x+3)-3(x-1)-(15)=0
We multiply parentheses
6x-3x+6+3-15=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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