2(3x+3)=3(2x+2)=2

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Solution for 2(3x+3)=3(2x+2)=2 equation: 



2(3x+3)=3(2x+2)=2

We move all terms to the left:

2(3x+3)-(3(2x+2))=0

We multiply parentheses

6x-(3(2x+2))+6=0



We calculate terms in parentheses: -(3(2x+2)), so:

3(2x+2)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

6x-6x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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