2(3x+3)=3(x+12)

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Solution for 2(3x+3)=3(x+12) equation: 



2(3x+3)=3(x+12)

We move all terms to the left:

2(3x+3)-(3(x+12))=0

We multiply parentheses

6x-(3(x+12))+6=0



We calculate terms in parentheses: -(3(x+12)), so:

3(x+12)

We multiply parentheses

3x+36

Back to the equation:

-(3x+36)



We get rid of parentheses

6x-3x-36+6=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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