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2(3x+3)=3(x+6)
We move all terms to the left:
2(3x+3)-(3(x+6))=0
We multiply parentheses
6x-(3(x+6))+6=0
We calculate terms in parentheses: -(3(x+6)), so:We get rid of parentheses
3(x+6)
We multiply parentheses
3x+18
Back to the equation:
-(3x+18)
6x-3x-18+6=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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