2(3x+3)=7(7x-9)

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Solution for 2(3x+3)=7(7x-9) equation: 



2(3x+3)=7(7x-9)

We move all terms to the left:

2(3x+3)-(7(7x-9))=0

We multiply parentheses

6x-(7(7x-9))+6=0



We calculate terms in parentheses: -(7(7x-9)), so:

7(7x-9)

We multiply parentheses

49x-63

Back to the equation:

-(49x-63)



We get rid of parentheses

6x-49x+63+6=0

We add all the numbers together, and all the variables

-43x+69=0

We move all terms containing x to the left, all other terms to the right

-43x=-69

x=-69/-43

x=1+26/43

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