2(3x+33)+3(x+11)=12

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Solution for 2(3x+33)+3(x+11)=12 equation: 



2(3x+33)+3(x+11)=12

We move all terms to the left:

2(3x+33)+3(x+11)-(12)=0

We multiply parentheses

6x+3x+66+33-12=0

We add all the numbers together, and all the variables

9x+87=0

We move all terms containing x to the left, all other terms to the right

9x=-87

x=-87/9

x=-9+2/3

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