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2(3x+4(3-x))=3(5-4x)
We move all terms to the left:
2(3x+4(3-x))-(3(5-4x))=0
We add all the numbers together, and all the variables
2(3x+4(-1x+3))-(3(-4x+5))=0
We calculate terms in parentheses: -(3(-4x+5)), so:We get rid of parentheses
3(-4x+5)
We multiply parentheses
-12x+15
Back to the equation:
-(-12x+15)
2(3x+4(-1x+3))+12x-15=0
We add all the numbers together, and all the variables
12x+2(3x+4(-1x+3))-15=0
We move all terms containing x to the left, all other terms to the right
12x+2(3x+4(-1x+3))=15
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