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2(3x+4(3-x))=3(5-4x)-1
We move all terms to the left:
2(3x+4(3-x))-(3(5-4x)-1)=0
We add all the numbers together, and all the variables
2(3x+4(-1x+3))-(3(-4x+5)-1)=0
We calculate terms in parentheses: -(3(-4x+5)-1), so:We get rid of parentheses
3(-4x+5)-1
We multiply parentheses
-12x+15-1
We add all the numbers together, and all the variables
-12x+14
Back to the equation:
-(-12x+14)
2(3x+4(-1x+3))+12x-14=0
We add all the numbers together, and all the variables
12x+2(3x+4(-1x+3))-14=0
We move all terms containing x to the left, all other terms to the right
12x+2(3x+4(-1x+3))=14
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