2(3x+4)+10=4(x-5)+28

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Solution for 2(3x+4)+10=4(x-5)+28 equation: 



2(3x+4)+10=4(x-5)+28

We move all terms to the left:

2(3x+4)+10-(4(x-5)+28)=0

We multiply parentheses

6x-(4(x-5)+28)+8+10=0



We calculate terms in parentheses: -(4(x-5)+28), so:

4(x-5)+28

We multiply parentheses

4x-20+28

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

6x-(4x+8)+18=0

We get rid of parentheses

6x-4x-8+18=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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