2(3x+4)+41=10x+3-4x+46

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Solution for 2(3x+4)+41=10x+3-4x+46 equation:



2(3x+4)+41=10x+3-4x+46
We move all terms to the left:
2(3x+4)+41-(10x+3-4x+46)=0
We add all the numbers together, and all the variables
2(3x+4)-(6x+49)+41=0
We multiply parentheses
6x-(6x+49)+8+41=0
We get rid of parentheses
6x-6x-49+8+41=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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